The reduction half equation of the following reaction is:
\(Zn_{(s)} + CuSO_{4(aq)} → ZnSO_{4(aq)} + Cu_{(s)}\)
a
\(Zn_{(s)} → Zn^{2+}_{(aq)} + 2e^-\)
b
\(CuSO_{4(s)} + H_2O_{(l)}\) → \(Cu^{2+}_{(aq)}\) + \(SO_{4(aq)}^{2-}\)
c
\(Cu^{2+}_{(aq)} + 2e^- → Cu_{(s)}\)
d
\(Cu^{2+}_{(aq)} + e^- → Cu_{(s)}\)
Explanation
Correct Option
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