At 2.0 atm pressure, the volume of a gas is 4.0 L. If the pressure is reduced to 1.0 atm while keeping the temperature constant, what will be the new volume of the gas?
According to Boyle's law, when the temperature is constant, the initial pressure multiplied by the initial volume is equal to the final pressure multiplied by the final volume. Mathematically, P1V1 = P2V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume, respectively. Using the given values:
(2.0 atm) * (4.0 L) = (1.0 atm) * (V2)
Solving for V2:
V2 = (2.0 atm * 4.0 L) / (1.0 atm) = 8.0 L
There is an explanation video available below.
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