What happens to the position of equilibrium, if a reversible exothermic reaction is subjected to a decrease in temperature?
The position of equilibrium shifts to the left
The position of equilibrium shifts to the right.
The position of equilibrium remains unchanged
The reaction stops
Explanation
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An increase in temperature will cause the equilibruim position to shift to the side with a higher heat content.
A decrease in temperature will cause the equilibruim position to shift to the side with a lower heat content.
In an EXOTHERMIC reversible reaction, the reactants have a higher heat content, therefore, if the system is subjected to a decrease in temperature, it will move to the right (the side with the lower heat content).
Hence, they are very correct.
Hope this helps!
And when temperature is decreased in an exothermic reaction the forward reaction is favoured so the equilibrium shifts to the right not the left.
It will shift to the right, because it is a decrease in an EXOTHERMIC reaction, not ENDOTHERMIC
I think it should be C the position of the equilibrium will continue in it's original direction since conditions still favor it but it might also be B not so sure
it's a reversible exothermic reaction meaning it can go from either side no one knows whether it's exothermic side is left or right all specified is that the side it proceeds in is exothermic if temperature is decreased it favours exothermic reactions more and it will continue in it's original direction meaning the equilibrium won't shift cause no constraint was placed but a condition to favor the original reaction so I really suspect C
The correct answer is B because in an exothermic reaction, when the temperature is decreased equilibrium position will shift to the right
the answer is B,in an exothermic reaction,decrease in temperature favours the forward reaction thereby shifting the equilibrum to the right,while increase in temperature favours the reverse(backward)reaction thereby shifting the equilibrum constant to the left so the most appropriate answer is B.
please make amendment.
The correct answer is "A. The position of equilibrium shifts to the left." When an exothermic reaction is cooled, the forward reaction, which releases heat, is favored, and the reaction shifts to the left to produce more reactants. This is because the system is trying to counteract the decrease in temperature by producing more of the products that release heat.
