If 30cm^{3} of oxygen diffuses through a porous pot in 7 seconds, how long will it take 60cm^{3} of chlorine to diffuse through the same pot, if the vapour densities of oxygen and chlorine are 16 and 36 respectively?

A.
9.3 sec

B.
14 sec

C.
21 sec

D.
28 sec

E.
30.3 sec
Correct Answer: Option C
Explanation
The rate of diffusion of a gas is proportional to the square root of the density.
16 and 7 secs
36 or 6 will be proportional to
7/16 x 6
7/4 x 6
But volume of chlorine is twice that of oxygen. The rate of escape of chlorine is
2/1 x 7/4 x 6/1 = 7 x 3; = 21 sec
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4 years ago
60cm3 of O2 will diffused in 60*7 / 30 = 14sec
Given: V.D of O2 (p1) = 16, Cl (p2) = 36
Calculated: t1 = 14sec, t2 = ?
Recall Graham's law of diffusion
\p2 t2. \36 t2. 6 t2
 =  i.e.  =  »»  = 
\p1 t1. \16 14. 4 14
Cross multiplying
t2*4 = 14*6
t2*4 = 84
t2 = 84

4
t2 = 21sec
Therefore 60cm3 of Chlorine will diffuse in 21seconds
NOTE: \ means Square root
 means division (all over)
/ also mean division
p (eg p1, p2) means density