If the molar mass of X(HCO3)\(_{2}\) is 162 g mol\(^{-1}\), determine the relative atomic mass of X. [H = 1.0, C = 12.0, 0 = 16.0]
Molar mass of X(HCO3)2 = X+(1+12+(16*3))2=162 =X + (13+48)2=162 X + 122=162 X=162-122 X=40
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