What volume of (dm\(^3\)) of water will be added to 10dm\(^3\) of 2.0 mol/dm\(^3\) HCL...

What volume of (dm\(^3\)) of water will be added to 10dm\(^3\) of 2.0 mol/dm\(^3\) HCL acid solution to give a final solution of 0.5 mol/dm\(^3\)?

To make a fixed amount of a dilute solution from a stock solution,

use the formula: C1V1 = C2V2

where: V1 = Volume of stock solution needed to make the new solution.

C1 = Concentration of stock solution.

V2 = Final volume of new solution.

C2 = Final concentration of stock solution

2 * 10 = 0.5 * V2

20 = 0.5V2

\(\frac{20}{0.5}\) = V2

= 40dm\(^3\)

There is an explanation video available below.

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