The reactions below represent neutralization reaction, in which of them is the value of ΔH highest?
a
CH\(_3\)CH\(_2\)COOH + KOH → CH\(_3\)CH\(_2\)COOK + H\(_2\)O
b
NH\(_4\)OH + HCL → NH\(_4\) + H\(_2\)O
c
NaOH + HCL → NaCL + H\(_2\)O
d
CH\(_3\)COOH + NaOH → CH\(_3\)COONa + H\(_2\)O
Explanation
Correct Option
cVideo Explanation
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Discussions (5)
Odemosad
1 year ago
NOTE: the value of highest ∆H is the one with less -ve value.
Option C having both Strong acid and base with values -57 to -58 KJ/mol is NOT the highest.
The highest should be -56 and above.
Correct Option is B. NH4OH + HCL → NH4 + H2O ( ∆H ≈ -51 to -52 KJ/mol)
Reason well, u will understand.
