N\(_2\)O\(_4\) ⇔ 2NO\(_2\) (Δ = -ve)
From the reaction above, which of these conditions would produce the highest equilibrium yield for N\(_2\)O\(_4\)?
high temperature and high pressure favor the highest yield for N\(_2\)O\(_4\)
high temperature favours the production of the reactant since it is endothermic, while high pressure favours the side involving a decrease in volume.
There is an explanation video available below.
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}