An organic compound which liberate carbon(iv)oxide from trioxocarbonate(iv) solution is likely to be?

a

C\(_2\)H\(_5\)OH

b

C\(_3\)H\(_4\)

c

C\(_6\)H\(_6\)

d

CH\(_3\)COOH

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Explanation

Correct Option
d

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Discussions (7)

Truss
1 year ago

The correct answer is:

D. CH₃COOH (Ethanoic acid/Acetic acid)

Explanation:

Acids react with carbonates and hydrogen carbonates to release carbon dioxide (CO₂).

Ethanoic acid (CH₃COOH) is a weak organic acid that reacts with trioxocarbonate(IV) (CO₃²⁻) salts to produce CO₂ gas.


For example:

2CH₃COOH + Na₂CO₃ \rightarrow 2CH₃COONa + H₂O + CO₂↑

The other options are not acids and therefore will not react with trioxocarbonates to release CO₂:

C₂₂H₅₅OH: An alcohol, which does not react with carbonates.

C₃₃H₄₄ and C₆₆H₆₆: Hydrocarbons, which do not have acidic hydrogen to react with carbonates.


Thus, CH₃COOH (Option D) is the correct answer.

ISRAELLEEDBOSS
2 years ago

correct

agadido
3 years ago

it's all part of neutralization

King33Victor
3 months ago

thw question is coming from Na2CO3 chemical properties

Odemosad
1 year ago

Among props of acids

Sensei
2 months ago

yes very correct

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