Br\(_{2}\) will oxidize CI\(^{-}\)
F\(_{2}\) has the least tendency to be reduced
Cl\(_{2}\) will oxidize I\(^{-}\)
l\(_{2}\) is a stronger oxidizing agent than F\(_{2}\)
Explanation
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Which of the following statements about elements in Group VII is correct?
A. Br2 will oxidize CI−
B. F2 has the least tendency to be reduced
C. Cl2 will oxidize I−
D. l2 is a stronger oxidizing agent than F2
Oxidizing Ability Decrease From Flourine to Iodine. Therefore A,D Is wrong. B is Wrong because Oxidizing Agent Undergo Reduction. So F2 should have the Highest Tendency to be reduced.
"B is correct" how?!!
oxidizing agents have the most tendency to be reduced and not the least tendency to be reduced the answer is C
The correct answer is:
C. Cl₂ will oxidize I⁻
Explanation:
Elements in Group VII (halogens) act as oxidizing agents, and their oxidizing strength decreases down the group (F₂ > Cl₂ > Br₂ > I₂). This means:
Cl₂ is a stronger oxidizing agent than I₂ and can oxidize iodide ions (I⁻) to iodine (I₂).
Now, let's analyze the other options:
A. Br₂ will oxidize Cl⁻ ❌ Incorrect
Br₂ is a weaker oxidizing agent than Cl₂, so it cannot oxidize Cl⁻ to Cl₂.
B. F₂ has the least tendency to be reduced ❌ Incorrect
F₂ is the strongest oxidizing agent, meaning it has the greatest tendency to be reduced to F⁻.
D. I₂ is a stronger oxidizing agent than F₂ ❌ Incorrect
I₂ is the weakest oxidizing agent among halogens, while F₂ is the strongest.
Thus, C is the correct answer.
Which of the following statements about elements in Group VII is correct?
A.
Br2 will oxidize CI−
B.
F2 has the least tendency to be reduced
C.
Cl2 will oxidize I−
D.
l2 is a stronger oxidizing agent than F2Which of the following statements about elements in Group VII is correct?
A.
Br2 will oxidize CI−
B.
F2 has the least tendency to be reduced
C.
Cl2 will oxidize I−
D.
l2 is a stronger oxidizing agent than F2
...B was picked as the answer, this is wrong because F2 has the highest tendency to be reduced as it is the most reactive halogen.
.. Please look into my complaint
