What is the concentration of a solution which contains 0.28g of potassium hydroxide in 100 cm\(^{3}\) of solution [KOH = 56]
0.01 mol dm\(^{-3}\)
0.05 mol dm\(^{-3}\)
0.10 mol dm\(^{-3}\)
0.50 mol dm\(^{-3}\)
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Discussions (3)
0.28g 
100cm3
x1000cm3
cross multiply
x=2.8g
mass conc=mass/molar mass
mass conc=2.8/56
=0.05
This way is far more better and understandable
since they said is concentration then our answer should be in mole per dm cube or gdm^-3
first and foremost extract the given lnformation out first no of gram= 0.28 g of potassium hydroxide
volume = 100 cm^3
molar mass= 56
we are looking for the concentration in moldm^3
comvert the volume 100cm^-3/1000= 0.1dm^3
we have gotten the volume
let go for the mole, to get the mole = mass/ molar mass
0.28g/56gmol^-3=0.005 mol
then the concentration will be mol/ vol since is in moldm^-3 the per is that division sign so you will just say 0.005 mol/0.1 dm^3 = 0.05 moldm^-3
