What number of moles of oxygen would exert a pressure of 10 atm at 320 K in an 8.2 dm\(^{2}\) cylinder?

[R = 0.082 atm dm\(^{3}\) mol\(^{-1}\) K\(^{-1}\)]

 

a

0.32

b

1.56

c

3.13

d

31.25

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Halab
4 years ago

PV=nRT
n=10*8.2/0.082*320
n=3.13 moles of oxygen

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