Na
Ag
Hg
Fe
Explanation
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Discussions (12)

D is very correct π―π―π―π―π₯π₯π₯
Fe + CuSOβ ===> Cu + FeSOβ
β¨ The metal that is use for recovering copper from copper sulphate should be a stronger reducing agent than the copper and should not react with waterπ€π€π€π€π€π€π€
Sodium metal reacts with water and will form sodium hydroxide and will not be able to reduce the copper from copper sulphate π₯π₯π₯π₯π₯π₯π₯π₯π₯π₯π₯π₯π₯π₯π₯π₯π₯π₯π₯π₯
Mercury and Silver can not be used to displace copper from the copper sulphate solution because Mercury and Silver are less easily oxidized than copperπ€π€π₯π₯π₯π₯π₯π₯π₯π₯π₯π₯π₯π₯π₯π₯π₯π₯ποΈποΈποΈποΈποΈποΈποΈποΈποΈποΈποΈποΈποΈποΈ

The correct answer is:
C. Copper(II) oxide (CuO)
Explanation:
Copper turnings (A): Copper metal does not react with dilute HβSOβ under normal conditions because it is below hydrogen in the electrochemical series and does not displace hydrogen from acids.
Copper(II) trioxocarbonate(IV) (B): CuCOβ reacts with dilute HβSOβ, but it produces effervescence due to the release of COβ gas.
Copper(II) oxide (C): CuO dissolves in warm dilute HβSOβ without effervescence to form blue copper(II) sulfate (CuSOβ):
Copper alloy (D): Alloys contain copper mixed with other metals (e.g., brass, bronze), and their reaction with dilute HβSOβ depends on the composition. However, most alloys resist reaction under normal conditions.
Since only CuO dissolves in warm, dilute HβSOβ without gas evolution while giving a blue solution, C is the correct answer.



