A solution of a mineral acid containing 0.10 mol of the acid per dm of solution. B IS a solution Containing 1.325g of anhydrous sodium trioxocarbonate (IV) per dm of solution.
(a) Put A into the burette and titrate with 20cm\(^3\) or 25cm\(^3\) portions of B using methyl orange as an indicator. Record the volume of your pipette
(b) From your results and the information is given, calculate;
(i) The number of mole of acid in the average titre
(ii) The number of mole of sodium trioxocarbonate (IV) in the volume of B pipette,
(iii) The mole ratio of acid to base in the reaction [H = 1, C = 12, O = 16, Na 23]
(c) Suggest what the acid in (a) Could be giving reasons for your answer. Hence, write the equation for the reaction.
Explanation
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