When 250 cm3 of a saturated solution of CuSO\(_4\) at 30°C was evaporated to dryness, 5.0 g of the salt was obtained..

What is the solubility of the salt at 30°C? [CuSO\(_4\) = 160]

Youri

4 years ago

solubility of salt = number of moles of salt / volume of solution

number of moles of salt = mass of salt / molar mass of solution = 5/160 = 0.03125 mol

volume of solution = 250cm3 = 0.25 dm3

solubility of salt = 0.03125/0.25

= 0.125 mol dm-3

Answer: B

Symply_symple

3 years ago

solubility (g/cm) = mass /molarmass × 1000÷volume

Youri

4 years ago

sammie 7