An alkanol containing 60% carbon by mass would have a molecular formula [H=1.0. C-12.0, O= 16.0]

Mezalabo

3 years ago

60% C
Alkanol general formula: CnH2n + 1 OH
C = 12, H = 1, O = 16
60% = Cn / CnH2n + 1 OH * 100
60 = 12n / 12n + 2n + 1 + 16 + 1 * 100
60 = 12n / 14n + 18 * 100
60 = 1200n / 14n + 18
840n + 1080 = 1200n
1200n - 840n = 1080
360n = 1080
n = 1080/360
n = 3
put n = 3 in CnH2n + 1 OH
molecular formula is C3H7OH

Iykay50

4 years ago

Find the percentage composition of carbon in each of the compounds in the options. e.g
MM of C3H7OH=60
C3=36
36/60*100=60%
Option C

Idowuayomideolaniyi

1 year ago

omoh 😕😫

Obioma4real

2 months ago

NICE ONE SIR, MY MENTOR, I JUST UNDERSTOOD THIS

nadida

3 years ago

the answer is B