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The oxidation of chromium in Cr\(_2\)O\(_7\)\(^{2-}\) ?

Chemistry
WAEC 2019

The oxidation of chromium in Cr\(_2\)O\(_7\)\(^{2-}\) ?

  • A. +4
  • B. +5
  • C. +6
  • D. +7
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Correct Answer: Option C
Explanation

Cr\(_2\)O\(_7\)\(^{2-}\) 

Cr\(_2\)O\(_7\) = - 2

Cr\(_2\) + O\(_7\) =  - 2

2Cr + 7(-2)  = - 2

2Cr - 14 = - 2

2Cr = -2 + 14

2Cr = 12

Cr = \(\frac{12}{2}\)

Cr = + 6


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