8g of CH\(_4\) occupies 11.2 at S.T.P. What volume would 22g of CH\(_3\)CH\(_2\)CH\(_3\) occupy under the same condition?
a
3.7dm\(^3\)
b
11.2dm\(^3\)
c
22.4dm\(^3\)
d
33dm\(^3\)
Explanation
Correct Option
bVideo Explanation
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De sage
1 year ago
lets show small work
mole = mass/MM
mass 22g
mole=?
mm= C3H8(44)
mole= 22/44
mole= 0.5
remember that
volume=mole×22.4dm³
volume= 0.5× 22.4
volume= 11.2dm³
you see The both are the same. 11.2 and 11.2
De sage
1 year ago
Avogadro's law states that the equal volume of all gases at a constant temperature and pressure contain the same number of molecules and volume.
