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2018 WAEC Chemistry Theory (a) (i)  Name the ore mostly used in the extraction of aluminium.   (ii)  Name two major...

Chemistry
WAEC 2018

(a) (i)  Name the ore mostly used in the extraction of aluminium.
  (ii)  Name two major impurities in the ore named in (a)(i).
  (iii)  Name the material used in making the electrodes in the extraction of aluminium.
  (iv)  Give two reasons why aluminium is commonly recycled.
  (v) Explain briefly why the anode has to be replaced at regular intervals during the extraction of aluminium.         

(b)  A current of 0.75 amperes was passed through an electrolysis containing chromium ions    for one hour and four minutes. If the mass of chromium deposited was 0.52 g, calculate the:

(i)    quantity of electricity passed;
(ii)    moles of chromium deposited;
(iii)  quantity of electricity required to deposit one mole of chromium;
(iv)  charge on the chromium ion.
[Cr = 52.0, 1 F = 96500 C]                                                 

(c)  In the contact process for the manufacture of tetraoxosulphate(VI) acid, the following reaction occurs:
2SO\(_2\)\(_{(g)}\) + O\(_2\)\(_{(g)}\)              2SO\(_3\)\(_{(g)}\)    H = - 197 kJ mol\(^{-1}\)

(i)   Name the catalyst used in the reaction;
(ii)  State the optimum temperature for this reaction;
(iii) What would be the effect on the yield of SO\(_3\) if a temperature higher than the optimum is used?      

(d)(i)  State two chemical methods by which temporary hardness of water can be removed.
(ii)  Write a balanced chemical equation for each of the methods stated in (d)(i).

 

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Explanation

(a) (i) -  Bauxite                                                           
(ii)  -   Iron (III) oxide
-     Silica / silicon (IV) oxide                   
-    Calcium trioxosilicate (IV)

(iii)-   Graphite / Carbon                  

(iv) -  uses less energy / power / electricity
-     conserves resources of ores / bauxite                         
-    less expensive/reduces cost
(v)-   Carbon anode reacts with oxygen     
-     Gas / CO\(_2\) given off                                                                                                            
(b)(i)  Q = It
Q = 0.75 x 64 x 60     
= 2880C     

(iv)   Number of Faradays = 288,000         
                        96,500          
                  = 2.984
               charge  = + 3           
           

(c) (i)  Vanadium (V) oxide  
(ii)   400 – 500\(^o\)C / 673 – 773 K
(iii)   the yield decreases     
                                                                                   

(d)(i) -  by boiling
-  by addition of(calculated amount of) Ca(OH)\(_2\) – Calcium hydroxide/slaked lime   
by addition of washing soda/Na\(_2\)CO\(_3\)
-  by addition of NaOH\(^-\) Sodium hydroxide/Caustic Soda
-  by ion exchange/ permutit

(ii)-  Ca(HCO\(_3\))\(_2\)\(_{(aq)}\)    boil      CaCO\(_{3(s)}\) + H\(_2\)O\(_{(l)}\) + CO\(_{2(g)}\)               
-    Ca(HCO\(_3\))\(_{2(aq)}\) + Ca(OH)\(_{2(aq)}\) → 2CaCO\(_{3(s)}\) + 2H2O\(_{(l)}\)  
-   Ca(HCO\(_3\))\(_2\)\(_{(aq)}\) + Na\(_2\)CO\(_{3(s)}\) → CaCO\(_{3(s)}\) + 2NaHCO\(_{3(aq)}\)
-   Ca(HCO\(_3\))\(_{2(aq)}\) + 2NaOH\(_{(aq)}\) → 2NaHCO\(_{3(aq)}\) + Ca(OH)\(_{2(aq)}\)
-   Ca(HCO\(_3\))\(_{2(aq)}\) + 2NaR → CaR\(_2\) + 2NaHCO\(_{3(aq)}\)


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WAEC Past Questions, Objective & Theory, Study 100% offline, Download app now - 24709
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WAEC May/June 2024 - Practice for Objective & Theory - From 1988 till date, download app now - 99995
WAEC offline past questions - with all answers and explanations in one app - Download for free
WAEC Past Questions, Objective & Theory, Study 100% offline, Download app now - 24709
Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts