If the cost of electricity required to discharge 10g of an ion X\(^{3+}\) is N20.00, how much would it cost to discharge 6g of ion Y\(^{2+}\)?

[1 faraday = 96,500C, atomic masses are X = 27, Y = 24]

Greatleesi1

5 years ago

Here is another method

De sage

1 year ago

guys lets solve it's simple ok.
for X ( lets find the quantity of electricity)

mass/ atomic mass= Q/eF
mass= 10g
Am =27
Q= ?
e=3+
F= 96500
substitute
10/27=Q/3×96500
cross multiply
27Q= 10× 3×96500
27Q= 2895000
therefore
Q=2895000/27
Q= 107222.2C


For Y
mass= 6g
Atomic mass=24
Q= ?
e= 2+
f= 96500
substitute
6/24=Q/2×96500
cross multiply
24Q= 6×2× 96500
24Q=1158000
therefore
Q= 1158000/24
Q= 48250C

now let find cost of Y
Q of X--->20
Q of Y---->x

Q of X = 107222.2C
Q of Y = 48250C
cost of X= 20
cost of Y=?

substitute
107222.2---> 20
48250------->x
cross multiply
107222.2x= 48250×20
107222.2x=965000
divide both sides by 107222.2
x= 965000/107222.2
x=9.00000

therefore cost of Y = 9

Award0001

2 years ago

Take proportionality sign as €
n € cost
n € 1/C (2nd law of electrolysis)

n € cost/C
n = k×cost/n
k = nc/cost

n1×c1/cost 1 = n2×c2/cost2

but n = m/mm

m1×c1/mm1×cost1 = m2×c2/mm2×cost2

m1 = 10g
mm1= 27g
c1 = 3
cost 1 = N20

m2= 6g
mm2 = 24g
c2= 2
cost 2 = ?

m1c1/mm1×cost1 = m2c2/mm2×cost2

10×3/27×20 = 6×2/24×cost2

30/540 = 12/24cost2
12×540 = 30×24cost2
6480 = 720cost2
cost2 = 6480/720 = N9