X is a substance which liberates CO\(_2\) on treatment with concentrated H\(_2\)SO\(_4\). A warm solution of X can decolorize acidified KMnO\(_4\). X is
HCOOH
NaHCO\(_3\)
FeCO\(_3\)
H\(_2\)C\(_2\)O\(_4\)
Explanation
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from Chemistry, if u remove Che from it, it becomes Mistry.
no be small thing we dey battle with. but God must see us true

We need a substance that:
Produces CO₂ with H₂SO₄.
Decolorizes acidified KMnO₄.
B. NaHCO₃ fits the first criterion but not the second.
A. HCOOH fits the second criterion but produces CO, not CO₂.
D. H₂C₂O₄ fits the second criterion but doesn't produce just CO₂ with H₂SO₄.
C. FeCO₃ fits both criteria.
The Answer
The best fit is C. FeCO₃ (Iron(II) Carbonate). It reacts with H₂SO₄ to produce CO₂ and Fe²⁺ acts as a reducing agent to decolorize KMnO₄.

