What volume of 0.100M sodium trioxonitrate (V) solution contains 5g of solute ?
[Na = 23, N = 14, O = 16]

CHUKWUKAMICHAEL

6 years ago

C X V MASS
_____ = _________
1000 RMM


0.100 X V/1000 = 5/85

CROSS MULTIPLY 8.5V = 5000
5000/8.5 =588.2m3
IL = 1000m3
IL = 588.2/1000
= 0.588L

THATS IT

probity06

5 years ago

Moles=5/86
Moles=0.0588
Molar conc.=moles/vol.
0.100=0.0588/vol
Vol=0.588litres

CHUKWUKAMICHAEL

6 years ago

C X V MASS
_____ = _______
1000 RMM


0.100 X V/1000 = 5/85

CROSS MULTIPLY 8.5V = 5000
5000/8.5 =588.2m3
IL = 1000m3
IL = 588.2/1000
= 0.588L

THATS IT

Martinsadedamola

2 years ago

mole of solute=concentration*volume
The mole mass of NaNo3 is Na= 23,N=14,O3=3*16=48
to find the no of moles of NaNo3 in 5g is moles=mass/molar mass
5/85=0.0588moles
v=0.0588/0.100=0.588l

Isahalhaji

1 year ago

help me solve this question