What volume of 0.100M sodium trioxonitrate (V) solution contains 5g of solute ?
[Na = 23, N = 14, O = 16]
Given:
V = ? , C = 0.100M, m = 5g
Molar mass, M of NaNO\(_3\) = 23 + 14 + (16 X 3) = 85 g/mol
Number of moles, n = \(\frac{mass}{Molar Mass}\)
= \(\frac{5}{85}\)
n = 0.0588 mole
Recall that n = \(\frac{CV}{1000}\)
n = CV (looking through the options, no need including the 1000 since the answer was left in Litres)
V = \(\frac{n}{C}\)
V = \(\frac{0.0588}{0.100}\)
V = 0.588 Litres
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