What mass of magnesium would be obtained by passing a current of 2 amperes for 2 hours 30 mins, through molten magnesium chloride?
[1 faraday = 96500C, Mg = 24]

Prince2006

3 years ago

The answer is meant to be 2.24 approximately NOT 2.00😠

Cvivian

4 years ago

Time is 2hours 30mins but you worked with 2hours. The correct answer is D

Bt1

2 years ago

Mass=Molar mass × current × time
____________________________
charge ×faraday
m= MIt/2F

m= 24*2*(7200+1800)
__________________
2 *96500
m = 432000/193000
mass =2.24g

frolphmerlin

3 months ago

the answer is supposed to be 2.24g of magnesium

rado8082

6 years ago

mass

Sodiqadegboye

1 year ago

the answer is 2.24

Adenikeeunice2000

6 years ago

M=Z*I*T
M= MASS IN GRAM=24g
Z=electrochemicalequivalent=Coulombs=?
I=current=2ampere
T=time in second=2hours30mins=9000second
M=I*T=2*9000=18000coulombs

18000C liberate 1/3*96500 *18000/1

But 1mole of mg=24g
Mass Of Magnesium liberated=1/3*96500 *18000/1 *24/1 g

Mass Of Magnesium=1*18000*24/289500

=1.50g

popson6

6 years ago

Q=it
7200+1800=9000
2×9000=18000
Mg in MgCl doesn't have any free electron sooo
24/96500= 0.00024

mass(M)= 0.00024×18000= 4.48
Mg= 4.48

Myschool come and recheck