A compound contains 40.0% carbon, 6.7% hydrogen and 53.3% oxygen. If the molar mass of the compound is 180. Find the molecular formula.
[H = 1, C = 12, O = 16]
C\(_3\)H\(_6\)O\(_3\)
C\(_6\)H\(_6\)O\(_3\)
C\(_6\)H\(_{12}\)O\(_6\)
CH\(_2\)O
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A. For molecular formula. .......... .................C. H. O. %: 40. 6.7. 53.3 ÷ by: M.N. 12. 1. 16. = 3.33. 6.7. 3.33. Now, divide by smallest no. (3.33) and then you have: I. 1. 2. 1. Therefore, the molecular formula= CH2O. For the empirical formula, ( CH2O)n =180 ( 12+ 2 +16)n = 180. 30n = 180. n = 180/30 =6. Therefore, the empirical formula = (CH2O)6 = C6H12O6
