A compound contains 40.0% carbon, 6.7% hydrogen and 53.3% oxygen. If the molar mass of the compound is 180. Find the molecular formula.
[H = 1, C = 12, O = 16]
C → 40/12 ≈ 3
H → 6.7/1 ≈ 6
O → 53.3/16 ≈ 3
dividing through with the lowest value, 3
C\(_1\)H\(_2\)O\(_1\)
[C\(_1\)H\(_2\)O\(_1\)]n = 180
[12 + 2 + 16]m = 180
30n = 180
n = 6
:C\(_6\)H\(_12\)O\(_6\)
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