Consider the equation below:
Cr\(_2\)O\(_7 ^{2-}\) + 6Fe\(^{2+}\) + 14H\(^{+}\) \(\to\) 2Cr\(^{3+}\) + 6Fe\(^{3+}\) + 7H\(_2\)O.
The oxidation number of chromium changes from
a
+5 to +3
b
+6 to +3
c
-2 to +3
d
+7 to +3
Explanation
Correct Option
bVideo Explanation
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