The heat of formation of ethene, C\(_2\)H\(_4\) is 50 kJmol\(^{-1}\), and that of ethane, C\(_2\)H\(_6\) is -82kJmol\(^{-1}\). Calculate the heat evolved in the process:

C\(_2\)H\(_4\) + H\(_2\) \(\to\) C\(_2\)H\(_6\)

a

-122kJ

b

-132kJ

c

-88kJ

d

-60kJ

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Petrina
6 years ago

∆H=∆P-∆R
∆H=-82-50=-132kj/mol
Ans B

Jeremiahyusuf
5 years ago

The work

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