2H\(^+\) + 2e\(^-\) \(\to\) H\(_2\)
2O\(^{2-}\) + 4e\(^-\) \(\to\) O\(_2\)
OCl\(^-\) + H\(_2\)O + 2e\(^-\) \(\to\) 2OH\(^-\) + Cl\(^-\)
Cl + e\(^-\) \(\to\) Cl\(^-\)
Explanation
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Discussions (12)
A. 2H⁺ + 2e⁻ → H₂
This is a reduction process. Hydrogen ions (H⁺) are gaining electrons to form hydrogen gas (H₂). The oxidation number of hydrogen decreases from +1 to 0.
B. 2O²⁻ → O₂ + 4e⁻
This is an oxidation process. Oxide ions (O²⁻) are losing electrons to form oxygen gas (O₂). The oxidation number of oxygen increases from -2 to 0.
C. OCl⁻ + H₂O + 2e⁻ → 2OH⁻ + Cl⁻
This is a reduction process. Hypochlorite ion (OCl⁻) is gaining electrons. The oxidation number of chlorine decreases.
D. Cl + e⁻ → Cl⁻
This is a reduction process. Chlorine atom (Cl) is gaining an electron to form chloride ion (Cl⁻). The oxidation number of chlorine decreases from 0 to -1.
Yeah.
Because its oxidation number at left hand side is -2 and at the right hand side is 0.
So it increased from - 2 to 0.
Note:
*Oxidation is addition of oxygen
*Removal of hydrogen
*Increase in oxidation number
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D is very correct.
if youre choosing B as the answer then A should aslo be correct.
