Correct Answer: Option B

Explanation

Solubility in \(gdm^{-3}\) = \(\frac{mass of salt in gram}{volume of liquid in dm^{3}}\)

200\(cm^{3}\) = \(\frac{200}{1000} dm^{3}  = 0.2dm^{3}\)

Solubility = \(\frac{0.2g}{0.2dm^{3}}\)

= 1.0\(gdm^{-3}\)

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