The oxidation number of nitrogen in \(Pb(NO_{3})_{2}\) is
\(Pb(NO_{3})_{2}\) = \(+2 +2N + (-2\times 6) = 0\)
= \(2N = 10\)
⇒ \(N = +5\)
Please don't post or ask to join a "Group" or "Whatsapp Group" as a comment. It will be deleted. To join or start a group, please click here
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}