Which of the following electron configurations represents the transition element Chromium \(_{24}Cr\)?

a

\(1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6} 4s^{2} 3d^{4}\)

b

\(1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}3d^{6}\)

c

\(1s^{2}2s^{2}2p^{6}3s^{2}3d^{4} 4s^{1}\)

d

\(1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{1}3d^{5}\)

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Correct Option
d

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Discussions (11)

Wrong. The answer is D

Johncak316
3 years ago

Since the last electron enters the 3d-subshell, the expected electronic configuration of Chromium (Cr)(Z=24) is

1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁴


But the observed electronic configuration is

1s² 2s² 2p⁶ 3s² 3p⁶ 4s¹ 3d⁵


The reason for this:-

We know that half filled & fully filled orbitals are stable. We also know that d-orbital can have maximum of 10 electrons. In Chromium, it is only one electron less than achieving the stable half filled electronic configuration & it also has somewhat similar energy as 4s orbital. So, it borrows ine electron from 4s-orbital & becomes half filled & stable.

Dr.Nuel
5 years ago

answer is D ooo... half filled orbitals tend to show stability hence they are most preferred

harthex4stiivoh
2 years ago

S orbital can contain 2 right so it's meant to be A

belau123
2 years ago

The correct answer is option A

LONGJOHN23
2 years ago

the answer is option A

Bravebee
4 years ago

They selected a wrong answer for the electron configuration of Chromium. The correct answer is meant to be (D) and not (A)

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