The position of equilibrium in a reversible reaction is affected by

a

particle size of the reactants

b

vigorous stirring of the reaction mixture

c

presence of a catalyst

d

change in concentration of the reactants

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Correct Option
d

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DrSponsor
1 year ago

The correct answer is:

โœ… D. Change in concentration of the reactant.
Why? ๐Ÿค“๐Ÿ‘€
The position of equilibrium in a reversible reaction is determined by Le Chatelierโ€™s Principle, which states that when a system at equilibrium is disturbed, it will shift to counteract the disturbance and restore balance.

Why is Option D Correct?

If the concentration of reactants is increased, the system will shift forward to produce more products.
If the concentration of reactants is decreased, the system will shift backward to produce more reactants.

For example, in the reaction:

N_2(g) + 3H_2(g) \leftrightarrow 2NH_3(g)

Removing NHโ‚ƒ will also shift equilibrium right to replace it.

Why Not the Other Options? ๐Ÿง๐Ÿ‘€

A. Particle size of reactants โŒ
Affects reaction rate, not equilibrium position. Smaller particles react faster but donโ€™t shift equilibrium.

B. Vigorous stirring โŒ
Only helps mix the reactants but does not affect equilibrium.

C. Presence of a catalyst โŒ
A catalyst speeds up both forward and backward reactions equally but does not shift the equilibrium position. It only helps the system reach equilibrium faster.

Now you understand! ๐Ÿ˜‡

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