The number of Hydrogen ions in 1.0\(dm^{3}\) of 0.02\(moldm^{-3}\) tetraoxosulphate(VI) acid is \([N_{A} = 6.02 \times 10^{23}]\)
a
\(1.2 \times 10^{22}\)
b
\(1.2 \times 10^{23}\)
c
\(2.4 \times 10^{22}\)
d
\(2.4 \times 10^{23}\)
Explanation
Correct Option
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Discussions (6)
Pavon4life
6 years ago
Yes because 1 mole of sulphuric acid contains 2 moles of hydrogen ions
Therefore 0.02 moles will contain 0.04 moles of hydrogen ion
1 mole of h =6.02*10 raised to power 23
0.04 moles will give 2.4 *10raised to power 22
Vmeche
3 years ago
The correct option should be "C" and not "A".
H2SO4 ----------> 2H+ + SO42-
1mol 2mol
=> 0.02mol 0.04mol
But 1mol of H+ contains 6.02 x 10^23
Therefore 0.04mol of H+ will contain 0.04 x 6.02 x 10^23
= 2.4 x 10^22
