What is the mass of solute in 500\(cm^{3}\) of 0.005\(moldm^{-3}\) \(H_{2}SO_{4}\)? ( H = 1, S = 32.0, O=16.0)
0.490g
0.049g
0.245g
0.0245g
Explanation
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Discussions (13)
the answer is wrong, the answer is C
number of moles = volume / 1000 * molar concentration
number of moles= 500/1000* 0.005
number of moles = 0.0025mole
number of moles = mass /molar mass
0.0025=mass/98
mass= 0.245
the answer is wrong.
m=n/Mm
n=n/v x 1000
0.005=n/500 x1000
n=0.005 x500/1000
n=0.0025mol.mol.
n=mass/Mm
0.0025=mass/98
mass=0.0025 x 98
mass=0.245g
The correct answer is "C", not "A".
1000cm3 of the solution contains 0.005mols of H2SO4
=> 500cm3 of the solution will contain 0.0025mol of H2SO4.
Recall: Mass = Mole x Molar mass
=0.0025mol X 98g/mol = 0.245g
=> 500cm3 of 0.005mol/dm3 H2SO4 contains 0.245g of H2SO4.
There is a fundamental error in the explanation. After the 500cm3, they changed the Concentration by multiplying by 2, thus changing the answer. The answer is 0.245g
The correct option is C and not A.
Please my school always make corrections and update your app in order not to mislead students.
Because I noticed that when errors and corrections are reported, you people ignored and will never review..... Is very bad.
My advice is to get a professional in each subject. So that any option chosen should be the correct one, alright
This simple problem, just look at the way you guys solved it. Am disappointed because the errors in this app are just too much. Please review every questions and answers in this app before ruining this great concept. Thank you!!
Please this answer is totally wrong
The formula to use here is
Mass/Molar mass=concentration in mol/dm³*volume
The correct answer is C please review
