An organic compound has the empirical formula \(CH_{2}\). If its molar mass is 42\(gmol^{-1}\), what is its molecular formula? (C = 12.0, H = 1.0)
a
\(C_{2}H_{4}\)
b
\(C_{3}H_{4}\)
c
\(C_{3}H_{6}\)
d
\(C_{4}H_{8}\)
Explanation
Correct Option
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Bl_4z3
2 years ago
MF = (Ef)n
MF =42
Ef = CH2
42 =(CH2)n
42 =(12+ 1*2)n
42 = (14)n
Divide both side by 14
42/14 =(14)n/14
n =3
Remeber {Ef]n
(CH2)n and n is 3
so (CH2)3 = C3H6

