H\(_2\) S\(_{(g)}\) + Cl\(_{2(g)}\) → 2HCl\(_{(g)}\) + S\(_{(g)}\) In the reaction above, the substance that is reduced is

a

H\(_2\)S

b

S

c

HCl

d

Cl\(_2\)

Download Offline App Ask a Question

Explanation

Correct Option
d

Video Explanation

Post your Contribution

Share:

Discussions (3)

Iyandadaniel
4 years ago

The answer is correct because reduction is the addition of hydrogen

Silenced
2 years ago

oxidation is addition of oxygen
no 2 please correct

markbalogban
7 years ago

correct

Quick Questions

Ask a Question
CO

ceoofwahala

20th June, 2026

Chemistry


2 comments

ASSAAS

20th June, 2026

English Language


5 comments

infinitehoaxx

21st May, 2026

Computer


4 comments