In electrovalency, the oxidation number of the participating metal is always

a

decreasing

b

increasing

c

constant

d

neutral

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Explanation

Correct Option
b

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Discussions (8)

Sammyporsche123
2 years ago

In electrovalency, the oxidation number of the participating metal is **increasing**. This is because electrovalency refers to the charge that an atom would have if all bonds were ionic. When a metal atom loses electrons during a reaction, it becomes positively charged, which means its oxidation number increases. So, the correct answer is **B. increasing**.

kiki009
3 years ago

you are saying B in the video and the answer writing here is C 😑😑

oyelamimariam
2 years ago

No the option is wrong, the correct answer is option B

DEWIZO
2 years ago

the correct ans is c the oxidation number of the participanting metal is always constant

marlianlawa
2 years ago

In electrovalency, which refers to the transfer of electrons between atoms to form ions, the oxidation number of the participating metal is always:

B. increasing

During electrovalent bonding, metals typically lose electrons to form positively charged ions (cations). As a result, the oxidation number of the metal increases because it loses electrons. On the other hand, nonmetals gain electrons to form negatively charged ions (anions), resulting in a decrease in their oxidation number.

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