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How many atoms are present in 6.0g of magnesium? [Mg = 24, N.A = 6.02...

Chemistry
JAMB 2018

How many atoms are present in 6.0g of magnesium? [Mg = 24, N.A = 6.02 x 10 \(^{23}\)mol]

  • A. 1.20 x 10\(^{22}\)
  • B. 2.4 x 10\(^{22}\)
  • C. 1.51 x 10\(^{23}\)
  • D. 3.02 x 10\(^{22}\)
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Correct Answer: Option C
Explanation

Using the formula, Number of moles = \(\frac{Number of atoms or molecules}{Avogadro number}\)

 Given: Mass of Magnessium = 6g

             Mass number of Mg = 24g/mol

Number of moles = \(\frac{mass}{Molar mass}\)

                            = \(\frac{6}{24}\) = \(\frac{1}{4}\) = 0.25 mole

Thus,  Number of moles = \(\frac{Number of atoms or molecules}{Avogadro number}\)

                       n  =  \(\frac{N}{L}\) 

                   0.25 = \(\frac{N}{(6.02\times 10\(^{23}}\) 

                   N = \(0.25 \times 6.02\times 10\(^{23}\))

                   N = 1.505 X 10\(^{23}\)

                   N = 1.51 X 10\(^{23}\)

There is an explanation video available below.


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Explanation Video

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