What volume of oxygen will remain after reacting 8cm\(^3\) of hydrogen gas with 20cm\(^3\) of oxygen...

What volume of oxygen will remain after reacting 8cm\(^3\) of hydrogen gas with 20cm\(^3\) of oxygen gas?

First we need to write the balanced chemical equation:

2H\(_2\) + O\(_2\) → 2H\(_2\)O

Reacting moles: 2 moles : 1 moles 2 moles

Expected reacting Volume: 8 cm\(^3\): 20 cm\(^3\)

Actual reacted Volume: 8 cm\(^3\): 4cm\(^3\) (Based on the balanced equation)

Residual Volume(Expected - Actual): 0cm\(^3\) : 16cm\(^3\)

Therefore, 16cm\(^3\) of Oxygen will remain after reacting 8cm\(^3\) of hydrogen gas with 20cm\(^3\) of oxygen gas.

There is an explanation video available below.

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