To what temperature must a gas at 273k be heated in order to double both its volume and pressure?

hafheez

7 years ago

USING GENERAL GAS EQUATION P1=1P P2=2P
V1=1V V2=2V
T1=273K T2=UNKNOWN SO LEGGO
V1 X P1 X T2=V2 X P2 X T1 INPUT UR VALUES T2=2V X 2P X 273 / V X P
T2=1092K

Valrichboy

7 years ago

P1v1/T1=p2v2/T2
Pv/273=2p×2v/T2
T2=4PV×273/Pv
T2=1092

solgade

1 year ago

a simple pattern

T2 = n² * T1
n = 2 (doubled)
T2 = 2² × 273
T2 = 4×273

Wumies

1 year ago

There's no explanation on the question ⁉️

Visioneverbrokeagain

3 months ago

just cram the answer
jamb no get time 😂

King33Victor

3 weeks ago

very correct