To what temperature must a gas at 273k be heated in order to double both...

To what temperature must a gas at 273k be heated in order to double both its volume and pressure?

Given:

T\(_1\) = 273K ; V\(_1\) = X ; P\(_1\) = Y

T\(_2\) = ? ; V\(_2\) = 2X P\(_2\) = 2Y ( Remember we were told the volume and pressure were doubled )

We also represented V\(_1\) and P\(_1\) to be X and Y respective,y since we were not given.

Using the formula: \(\frac{{P_1}{V_1}}{T_1}\) = \(\frac{{P_2}{V_2}}{T_2}\)

T\(_2\) = \(\frac{{P_2}{V_2}{T_1}}{{P_1}{V_1}}\)

= \(\frac{{2Y}\times{2X}\times{273}}{{Y}\times{X}}\)

= 2 x 2 x 273

= 1092 K

There is an explanation video available below.

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