From the diagram above, find the amount of solute deposited when 200 cm\(^3\) of the solution is cooled from 55°C to 40°C.

Wunderkind1

9 years ago

55°c=7moles

40°c=6moles

7-6=1mole

1000cm^3=1mole

200cm^3=x

x = 200*1/1000

x =0.20 mole

Erudite_Scholar

5 years ago

55°c=7moles

40°c=6moles

7-6=1mole

1000cm^3=1mole

200cm^3=x

x = 200*1/1000

x =0.20 mole

owuapu

5 years ago

somebody please explain to me, am lost

DesmondBuwaX

2 days ago

somebody say Merlin

markkdman

9 years ago

Please someone should explain

azekah

1 year ago

hahaha 🤣 this graph no blind balnk graph

Jonbellion

1 year ago

as how naa 😭

Aghepromise

6 years ago

Pls, i need an explanation. I have problems with stoichiometry. Solve on paper, snap and send to me pls. Facebook: Aghe Oghenetega Promise. Email: aghepromise18@gmail.com whatsapp: 09072914814

Aghepromise

6 years ago

Plz, explain in a sheet of paper, snap and send to me.

Sensei

1 month ago

💟👀👀👄

micann

1 year ago

more explanation pls.