The relative atomic mass of a naturally occurring lithium consisting of 90% \(^7 _3\)Li and \(^6 _3\)10% Li is

a

6.9

b

7.1

c

6.2

d

6.8

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a

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Discussions (19)

cyphar0101
7 years ago

6.9 is the correct answer.
masses are 7Li and 6Li
7 ร— 90/100 + 6 ร— 10/100
= 6.3 + 0.6
= 6.9

Udimbok
10 years ago

When i worked mine, it gave me 6.9 and not 6.2. The masses are: 90% 7Li and 10% 6Li

kushylyon
10 years ago

I just tire o

Peter Umoh
11 years ago

Pls is any of dis question in jamb pas qustns?

Qudrat Opeyemi
11 years ago

Please anyone with an explanation should help us out

iremical
10 years ago

the questn should carry their atomi no ratio

ifeoluwaobiwale
6 years ago

7*90/100 + 6*10/100=6.3+0.6=6.9
The question is not complete

Sensei
1 month ago

ancestors ๐Ÿ˜ญ๐Ÿ˜ข

glorihar
11 years ago

explain oh

S.o.m.t.o
7 years ago

Its 90% 7Li and 10% 6Li from there
7ร—90/100 + 6ร—10/100
63/10 + 6/10
6.3+0.6=6.9

5lyhigh
10 years ago

Natural relative atomic mass = 6.941

90%*10%*6.941 =0.62469=6.2469= 6.2

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