If 100cm3 of oxygen pass through a porous plug is 50 seconds, the time taken for the same volume of hydrogen to pass through the same porous plug is? [O = 16, H = 1]
a
10.0s
b
12.5s
c
17.7s
d
32.0s
Explanation
Correct Option
bVideo Explanation
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Homeostatics
2 years ago
easy tip for people that will come across the question in the future
simply do
V1T2/V2T1 use charles law as mnemonic but know that its comstant dont change the formular
this formula is for calculating graham law for time especially
so its say 100cm3 o2 that's V1 at 50secs that T1
and hydrogen again as volume is V2 being 100cm3 from the question
they said that we should find T2
so therfore V1T2/V2T1 =โM2/M1
so substitute 100T2/ 100*50 =โ1*2/16*2
100T2/5000=โ2/32
0.02T2 =โ0.0625
0.02T2=0.25
so coefficient of T = 0.25/0.02
=12.5secs .
note when to use formular is only when talked about time and they gave only 2 vol and a time 



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