Calculate the amount in moles of silver deposited when 9650C of electricty is passed through...

JAMB 2017

Calculate the amount in moles of silver deposited when 9650C of electricty is passed through a solution of silver salt [= 96500 Cmol^-1]

A. 0.05
B. 10.80
C. 10.00
D. 0.10

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Correct Answer: Option D

Explanation

m = \(\frac{Mm \times Q}{96500n
}\)

where Q = IT

M = Mm × \(\frac{Q}{96500n}\)

where m = mass

Mm = Molar mass

Q = Quantity of electricity

n = number of change= +1

\(\frac{M}{Mm}\) = mole = \(\frac{mass}{Molarmass}\)

\(\frac{M}{Mm}\) = \(\frac{Q}{96500n}\)

= \(\frac{9650}{96500n}\) × 1

= \(\frac{1}{10}\) = 0.1mol

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