The mass of silver deposited when a current of 10A is passed through a solution of silver salt for 4830s is – (Ag = 108 F = 96500(mol-1)

Deepa

3 years ago

Mass deposited=relative molecular mass × current× time in seconds÷charge × faraday


To put it simply
M=RAMIT/CHARFA

lamhace

7 years ago

Baba who tell u say 108 na gram for the question?

54.0g is actually the answer.
lemme come and be going

Teddy45

2 months ago

upcoming jambites use:
m=MIt/cf

qudus2019

8 years ago

The correct answer is B.
193000 produced 108 g then 48300 will produce 27.0g