A given mass of gas occupies 2dm³ at 300k. At what temperature will its volume be doubled, keeping the pressure constant?

godstamtam

7 years ago

V1=2dm or 20cm
V2= double of V1 which is 4dm or 40cm
T1= 300k.. nb no conversions should be made
T2=?(unknown)
Using the law V1/T1=V2/T2
; T2=V2*T1/V1
=4*300/2 = 600

SoSoSplendy

5 years ago

V1=2×1000(converting to cm)
v2= 2×2000(double the initial volume)
T1=300k
T2=?
v1/T1=V2/T2
T2=300(T1)×4000(v2)
_________________ =600k
2000(V1)
Understood??

FahleJunior

2 years ago

given the formula V1/T2=V2/T2
V1=1dm³ T1=300k V2dm³(doubled volume) T2=?

1/300=2/T2
cross multiply
T2=600k

kosisochukwuozochukwu

7 years ago

hmmm interesting

LoveAngela

8 years ago

how come of the 2

Sensei

2 weeks ago

I low-key knew 🙂

Haywhy346

8 years ago

Kelvin is to be converted to centigrade