Chemistry
JAMB 2017
A given mass of gas occupies 2dm
3 at 300k. At what temperature will its volume be doubled, keeping the pressure constant?
-
A.
400k
-
B.
480k
-
C.
550k
-
D.
600k
Correct Answer: Option D
Explanation
At constant pressure connotes Charle's law
\(\frac{V_1}{T_1}\) = \(\frac{V_2}{T_2}\)
\(\frac{2dm^3}{300k}\) = 2 x \(\frac{2dm^3}{T_2}\)
T
2= 600k
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