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The number of oxygen molecules present in 16.0g of the gas is ______? [Avogadro's number...

Chemistry
WAEC 2015

The number of oxygen molecules present in 16.0g of the gas is ______?
[Avogadro's number = 6.02 x 1023]
  • A. 6.02 x 1022
  • B. 6.02 x 1023
  • C. 3.01 x 1023
  • D. 1.51 x 1023
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Correct Answer: Option C
Explanation
1 mole = Molar mass of gas = Avogadros number
32g of O2 = 6.02 x 1023
16g of O2 = x
x = \(\frac{16 \times 6.02 \times 10^23}{32}\) = 3.01 x 1023

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